# Cross Curves in Freeship

Discussion in 'Software' started by lewisboats, Oct 13, 2009.

1. Joined: Oct 2002
Posts: 2,329
Likes: 126, Points: 0, Legacy Rep: 1603
Location: Iowa

### lewisboatsObsessed Member

Ok...so could someone explain how to interpret cross curves? I understand that the left side is the distance from the keel to the center of buoyancy and the bottom is the displacement. What would an almost flat line for a curve indicate? What do the higher heel angle lines indicate when they curve the opposite direction of the lower ones (humped up instead of sloped down or flat-ish) and why when I put in a single displacement does the graph change to straight lines angling up and to the right...stopping at the displacement set (or as close as the increments will allow).

Steve

PS: Yes I read the manual and from the page to my brain it becomes confusing because KN sin(ø) is a meaningless statement to this non math person. From another thread I found out that this MIGHT be the Transverse Center of Buoyancy at angles of heel but I may not be reading that correctly at all so.....HELP!

2. Joined: Oct 2008
Posts: 6,566
Likes: 593, Points: 113, Legacy Rep: 2488
Location: Japan

The "KN" is on the left hand side of the graph. The Displacement, is on the base of the graph.
You then have a series of curves all plotted at various 'angles'.

Select the displacement of the vessel, then draw a straight perpendicular from the displacement. Where this vertical line crosses the curves of angles, note the angle, and then note the value of KN.

First thought, you need to be sure that KN, is from the baseline/keel of the boat to the metacentre. (not all produced like this).

Then once you ahve the KN data you do the following:

GZ = KN - KG x sin (angle)
where
KN = cross curve ordinate
KG = centre of gravity above datum (Same datum as KN, corrected for free surface effects)
angle = heel angle, from cross curves

So, you draw up a table of the items you have
Angle, going down, and going across you have columns of
Angle, KN, sin (angle), KG x sin(angle), GZ.

3. Joined: Mar 2014
Posts: 67
Likes: 0, Points: 6, Legacy Rep: 10
Location: NZ

### terrnzJunior Member

Freeship cross curves and righting moments.

Excuse the resurrection of this old thread.

I have been working with FreeShip and in particular the curves of stability.

My project is a sailing yacht.

Is the formula GZ=KN - KG x sin (angle) valid if KG is negative?

my datum is the lowest point of the canoe body (Tc) Then I have a deep fin keel with a lead bulb and a ballast ratio of 55% so the centre of gravity is actually around 0.5m below the bottom of the hull.

I am also working with just one displacement (light ship mode)

also up to what angles is formula valid.

My purpose is to get a meaningful figure for the 30 deg heeling moment to use in mast inertia calculations.

4. Joined: Oct 2008
Posts: 6,566
Likes: 593, Points: 113, Legacy Rep: 2488
Location: Japan

5. Joined: Aug 2004
Posts: 2,737
Likes: 341, Points: 83, Legacy Rep: 2040
Location: Port Orchard, Washington, USA

### jehardimanSenior Member

KN curves really aren't useful for a sailing yacht. They are designed to quickly allow the calculation of GZ for vessels that greatly change their KG and draft, like cargo ships. Better to calculate moment to heeling moment directly, especially due to the lack of wall sided-ness and buoyancy distribution on most yachts.

6. Joined: Sep 2011
Posts: 6,156
Likes: 286, Points: 93, Legacy Rep: 300
Location: Spain

### TANSLSenior Member

The formula GZ = KN - KG x sin (angle) is valid for all heel angles.
You need to place your baseline through the bottom of the keel bulb and take all measurements with respect to that line. This way your KG will be positive.
In order to calculate the mast, in my opinion, you should use the ship's displacement at full load, which will normally be the worst situation that can occur.

7. Joined: Mar 2014
Posts: 67
Likes: 0, Points: 6, Legacy Rep: 10
Location: NZ