calculating weights in a Inclining Test of a barge

Amingenieria1980

New Member
Joined
Sep 4, 2019
Messages
3
Reaction score
0
Location
Panama
Can someone help me with a formula to calculate the weights necessary to use in a inclining test of a non self-propelled barge with measures of 55 x 11.8 x 1.75 m?
 
Welcome to the forum.

You will need to know roughly the displacement and the GM of the vessel to arrive at an approximate amount of weight.
 
You will need to know roughly the displacement and the GM of the vessel to arrive at an approximate amount of weight.
Wow, GM ????, what for?:confused:

weight to move, W (kg) :

W = disp * (Rmt + KC) * Tan(alfa) / (dist)

disp = displacement in the conditions of inclining test, kg
Rmt and KC in the conditions of inclining test, metres
alfa = expected angle of inclination
dist = distance of weight transfer, measure from center line, in meters
 
Last edited:
Rmt and KC in the conditions of inclining test, metres

Please explain - clearly without ambiguity and endless misdirection - how the OP arrives at these figures based upon the data supplied?
 
I can't believe you need an explanation. It's the dumbest thing I still had to hear. But, if you really need it, raise your specific doubt and I will gladly explain it to you.
As for the OP, I will gladly try to help you and explain everything he needs, if he needs it. It is very likely that he needs fewer explanations than you.
By the way, and as a result of your post, have you ever done an inclining test and calculated the light weight of a boat? If you have done so, you should not raise those doubts.:)
 
Please explain - clearly without ambiguity and endless misdirection - how the OP arrives at these figures based upon the data supplied?

And...

But, if you really need it, raise your specific doubt and I will gladly explain it to you.

Comprehension really is not your strength at all...
So, for the hard of reading... please explain how you arrive at your:

Rmt and KC in the conditions of inclining test, metres

From the data provided by the OP.
 
So, let me get this right. The question the OP asked is this:

...Can someone help me with a formula to calculate the weights necessary to use in a inclining test..

Your reply is thus:

Rmt and KC in the conditions of inclining test, metres

So, naturally it begs the question:

Please explain - clearly without ambiguity and endless misdirection - how the OP arrives at these figures based upon the data supplied?

Initially, you said:

.., if you really need it, raise your specific doubt and I will gladly explain it to you.

But now, your reply is thus:

I refuse at all to explain to you, that you say you are a naval architect, how the Rmt and the KC are calculated.

See, this is where comprehension and understanding in a debate is so lacking...

The question is how do YOU calculate it...the question has nothing to do with me. The statement of Rmt et al, is made by YOU and no one else.

Thus, either YOU know how to calculate the Rmt that you cite , based upon the data supplied by the Op or you don't.

If YOU do, please provide the solution, as the Op is waiting you expert reply.
If YOU don't, please say so.

Which is it..?
 
I know that you should know the formula that I have written, express each term of it as it is expressed. I don't know if you become ignorant, with the stupid idea of discrediting me, or if you really are to the extreme that I couldn't imagine.
It is not worth talking to you because, apparently, you are not able to understand the basics. I am not going to waste any more time to show you what, apparently, despite being a naval architect, you are unable to assume.
But, speaking about the post #2, why do you tell the OP that he should estimate the value of GM ?. What for?, Could you, please, with your perfect English, explain it? Or is it a blunder when talking about what you don't know?
 
Can YOU please define Rmt as you noted here:

Rmt and KC in the conditions of inclining test, metres

Either you can or you cannot.
 
Rmt = Radio metacéntrico transversal.
You (well someone who knows the subject) would probably have written in correct English "transverse metacentric radio". Easy, right? I can't believe you haven't been able to guess it. It doesn't say much about your mental agility although I must admit that I should write so that even the dumbest can understand what I say.
What do you tell me now, that you have already left doubts, of GM?
By the way, since you do can give me English lessons, is it more correct to write YOU than just you?:D

Edited Sep 8, 2019 at 8:34 AM : Following the affectionate advice of Ad Hoc, I wish to clarify that when I have translated Rmt as "Metacentric transversal radio" I have made a mistake due to my little ease with the English language. Actually I had meant "Metacentric transverse radious". It is possible that the translation is still not perfect but I think that now, even those who do not dominate the naval architecture, will be able to fully understand the formula of post # 3. I'm sorry because such a silly mistake has resulted in an even more silly thread. As far as I'm concerned, I apologize.
 
Last edited:
Rmt = in correct English "transverse metacentric radio". Easy, right?

Okay - now we are getting somewhere.
Firstly, I've no idea what a "radio" in this context means? Are you listening to music while doing this?

So in words, how do you calculate this Rmt?
 
.. and then you will ask me how do I calculate the value of KC, and then how do I calculate "disp" and then how do I calculate alpha and then how do I calculate "dist", and then .... Don't you think that Is it time to leave this stupid questionnaire?
If you really don't know how to calculate what I call "Rmt", you should review your textbooks. If, after that, you still don't know, I will gladly explain it to you but you should remove that pompous "Naval Architect" from your firm since, in that case, even if you have the title, you don't have the necessary knowledge to use it.
By the way, smart joke about "listening to music", I didn't expect less from you. :D
What about estimating the GM? What should the OP do with that advice? Keep it among the collection of stupidities read in this forum?:)
 
.. and then ....

So, that's a NO then is it?

Remember this is YOUR citation, no one else's. Thus can you explain your citation or not?
 
Forum posts represent the experience, opinion, and view of individual users. Boat Design Net does not necessarily endorse nor share the view of each individual post.
When making any potentially dangerous or financial decision, always employ and consult appropriate professionals. Your circumstances or experience may be different.

  • Back
    Top