Wait, so to find the friction from the WSA it is what I did before but I have to add that to the from drag which is equal to = 1/2 x 1000 x...

Could you say what these sources are? I need to reference my work. So the drag coefficient would be 1.55 for all models? The drag that the...

somewhere in the middle with neutral buyoancy

between 2 and 2.5 meters

Ok so for the speed: I posted a diagram before of how the experiment was set up here it is again,[ATTACH], so the second pulley had a sensor in it...

I agree with the top and bottom part being 1315.4 cm^2 but not the sides being 684cm^2. The side is made of three sides of the rectangle (20x3.9 +...

WSA would be the surface area of the whole model right? If it is than my calculation with 3.9cm as depth are correct.

Yeah I forgot to type the 1/2 bit but I did do it. Ok so I got for the 120 degree boat with a 96.6g mass pulling it: average velocity = 1.45m/s,...

Ok, that helps. It wasn't deep under water. The first three boats (120, 100, 80) were always submerged but close to the surface, however the other...

Haha ok, so I calculated wave drag like Ad Hoc suggested and plotted the waved drag against total drag (equal to weight pulling boat forward) for...

When I said under water a literally mean that the whole boat was submerged, like a submarine. For the boats with the smaller angle being pulled by...

Thank you for your suggestions. I will not have time to test the friction of the pulley but it is certainly something that I am going to mention...

Ad Hoc, first of all thank you for your time and input. Yes what I want to do is investigate the angle of entrance with total resistance. With...

Thank you seadreamer6, Gonzo and David for all your compliments and the help you have given me this far. So first, David, I did what you told me...

Ok so I am attaching a diagram of my experiment to show exactly how I did it. I used three different masses for each boat (96.6g, 196.7g and...