..Something like, any 3 or 4 inch beam is sufficient", etc. I' be very grateful...
Happy New Year to you Michael.
This is a very simple straight fwd exercise.
But first you need to set your assumptions and goal/objective!
In my language, your engine weighs 272kg and the span is 1.623m.
Being aluminium the objective is to satisfy the deflection. Since aluminium is a low modulus material, it is driven by deflection and not stress.
So, what deflection is appropriate?
In general one could say 1/100th of the span...this equates to 16.2mm. But considering the item that it is supporting i would suggest this is too high.
A value of around 10mm is "reasonable". However, again, considering the item that is being supported half this value would be more appropriate i.e 5mm, deflection.
Now the load we can consider this to be a point load, not a UDL. It makes no sense to analyis this as a UDL or even a partial UDL. Again - because of the item that is being supported.
So, again, we can add another "factor of safety", by assuming the beam is supply supported - rather than built-in. In reality this is not the case, as the ends will have support to prevent the beam ends moving and also to transfer the load from the beam into the hull....this is also a very very important part of the structural design that you must address!!!
So we shall assume a S/S analysis with a max deflection of 5mm.
Finally the load, the 272kg. We shall assume a nominal 1g loading added to this....therefore, a load of 544kg.
And since, looking at your dwg it appears 2 beams are supporting this engine..which makes sense, not 1, this must be supported by at least 2 beams...then each beam will experience 272kg or 2668N of load.
Thus the max deflection = W.L^3/(48.E.I)
Where I = the 2nd moment of inertia of the beam.....we can rearrange this to have I = W.L^3/(48.E.deflc)
With a deflection of 5mm, the I = 688,863mm^4, or 6.9 x 10^5 mm^4
The stress is simply = M/Z
So, now, what is the design allowable stress?
Noting Regs rules..i.e. Class rules...and the fact this is 6061, and considering you will attach this to the hull - in some form - it will most likely be welded.
Therefore your design allowable stress = 76.8MPa.
This gives a modulus of = M/Stress = 14.2 cm^3
So, we now need a beam that satisfies the I and the Z.
Looking at the list the AA-5 beam has a Z = 23.4cm^4...so this is ok, and the I = 9.13 x 10^5 mm^4
These values are over the calculated minimums. But considering many issues can go wrong, more FoS the better.
Finally the shear stress. Given the web thickness of 0.13inches = 3.302mm and the web height of 66.04mm, this gives a shear stress of 6.1MPa, which is below the 43.2MPa.
Thus it is as simple as that.
But you must be very careful how you attached the beams and transfer this load into the hull.
Good luck.
EDIT... you must realise the above calc's, this is the bear minimum requirement based upon a simple set of data.
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