Small Barge Draft

Discussion in 'Stability' started by Tevita Lauvili, Dec 8, 2014.

  1. Tevita Lauvili
    Joined: Nov 2014
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    Location: Fiji

    Tevita Lauvili Junior Member

    I would like to make a pontoon barge that would approximately weigh 2tonnes with dimensions as follows;

    length- 6m
    beam- 2m
    height- 1.5m

    I would like the draft to be 0.45m when pontoon barge is empty.
    What i would like to know is how can i find out the actual draft of the pontoon barge when empty in seawater.


    Tevita
     
  2. gonzo
    Joined: Aug 2002
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    Location: Milwaukee, WI

    gonzo Senior Member

    The underwater volume, in cubic meters, will be the weight of the barge divided by 1026 Kg.
     
  3. Tevita Lauvili
    Joined: Nov 2014
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    Location: Fiji

    Tevita Lauvili Junior Member

    Thanks
     
  4. TANSL
    Joined: Sep 2011
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    TANSL Senior Member

    If the weight is given in Kg, that operation will give a dimensionless result. (not in cubic meters). :confused:
    (I guess 1026 is the specific gravity of seawater)
    In any case, it would only be true if the block coefficient is equal to one (Cb = 1), which is unlikely.
     
  5. gonzo
    Joined: Aug 2002
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    Location: Milwaukee, WI

    gonzo Senior Member

    Block coefficient is not related to the submerged volume, it is a ratio of dimensions.
     

  6. TANSL
    Joined: Sep 2011
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    TANSL Senior Member

    Amazing. I will not comment. The participants in this forum can judge for themselves how far goes knowledge the others have.
    What everyone writes is enough to disqualify him self.
     
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