Non dimesionalizing ship's moment of inertia

You could make it a function of the ship's Beam.

Such as (Beam/x)^4

This way you should get the same actual amount no matter which unit of measurement you used (not the same number), whether you use feet, cubits, meters, or centimeters.
As Heimfried correctly noted in the previous page (it is always useful to read the thread first) - the above non-dimensionalization formula would be valid only if the talk is about the Area moment of inertia, or Second moment of area, which is a geometrical propriety of an area: https://en.wikipedia.org/wiki/Second_moment_of_area

It is very different from the Moment of inertia, which is a mass property of a body and is of interest in the study of the body dynamics: https://en.wikipedia.org/wiki/Moment_of_inertia
 
".........the force acting on the 10 kg (4.54 lb) body will have..........."
Guess you were just making sure I was paying attention here, 22 LB mass?
No, it was a pure, genuine and sincere conversion error. :D
One more reason to stick to units one is most familiar with (mine are SI).
I have corrected the error, thanks for noting it.
 
Mass moment of inertia or transverse waterplane moment of inertia?

The latter can be compared to that of a rectangle of L by B and is typically the waterplane coeffiecient squared.
 
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