daiquiri
Engineering and Design
- Joined
- May 31, 2004
- Messages
- 5,370
- Reaction score
- 259
- Location
- Italy (Garda Lake) and Croatia (Istria)
Don't know what are you aiming at, but IMO you are overthinking it anyways.If symmetric hulls are the lowest drag, but get asymmetricated by the boundary layer, then the real lowest drag shape should be symmetric minus the shape of the boundary layer, so that the BL fills in the shape and creates a virtual symmetric shape, is that right? That is probably not even possible. edit Also with the boundary layer being gradual, it wouldn't be as clear-cut as it sounds.
If Delta(L) is the displacement BL at the transom of a L-meters long and B-meters wide hull, then the order of magnitude of the ratio Delta(L)/B is typically 10^-3. In other words, the maximum thickness of the displacement BL is only 0.1% of the ship's beam. How much influence can that have on the final result of the optimization and on the residual drag? IMO, almost none.