How to calculate the current going between batteries?

Discussion in 'OnBoard Electronics & Controls' started by mascip, Sep 10, 2015.

  1. Joakim
    Joined: Apr 2004
    Posts: 892
    Likes: 52, Points: 28, Legacy Rep: 422
    Location: Finland

    Joakim Senior Member

    Diode voltage drop is not at all constant, it depends on the current. Here are two diodes that could be used for battery isolation

    Standard:
    http://www.genesicsemi.com/images/products_si/super_fast_rec/murh10005_thru_murh10020r.pdf

    Schottky:
    http://www.vishay.com/docs/94581/vs-100bgq10.pdf

    Voltage drop at 100 A:
    Standard 1-1.7 V
    Schottky 0.9-1.4 V

    Voltage drop at 10 A:
    Standard 0.75-1.0 V
    Schottky 0.4-0.6 V

    Voltage drop at 1 A
    Standard 0.7-0.8 V
    Schottky 0.2-0.4 V

    These one seem to use big Schottky diodes, since voltage drop is 0.45 V at rated current and 0.3 V at low current: https://www.victronenergy.com/upload/documents/Datasheet-Argo-Diode-Battery-Isolators-EN.pdf
     

  2. gonzo
    Joined: Aug 2002
    Posts: 14,132
    Likes: 538, Points: 123, Legacy Rep: 2031
    Location: Milwaukee, WI

    gonzo Senior Member

    Ultimately, the voltage drop is irrelevant. The voltage regulator will take care of it.
     
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