Giving this some thought it is not difficult to come up with an aluminum cross section that will carry the load that the existing solid 3 inch spruce mast would carry. I am assuming that
the exising 3 inch diameter is designed to allow for whatever factor of safety that you are comfortable
Not sure where you are on terminology therefore:
Load is a force-------------------units--pounds force
Stress is the force per area------unit--pounds force per square inch= sigma = symbol S
Moment is the multiplication of the equivalent force acting at some distance from the bottom of the mast to the spot where the variable loads acting on the mast can be replaced
by a single force. ------------------units-- inch x pounds (pound inches) = symbol M
c is the distance from the center to the outer edge of the cross section---unit inches
I is the moment of inertia of the cross section=units--inches to the fourth power = symbol I
The moment in a cantilevered beam will produce the maximum allowable stress of 6700 psi for spruce at the bottom of the mast. ( might not not precisely correct)
The calculations will be for a 3 inch solid spruce mast
Sigma =Mc/I
Sigma max = 6700 inch pounds
c - 1.5 inches diameter divided by 2
I for a 3 inch cross section is 4 inches to the fourth.
The Maximum moment that this mast can carry is
6700 = M x 1.5 /4 M then equals the moment that the forces on the sail will produce until the allowable stress is reached which is about 18,000 inch pounds
Taking this Moment and inputting into an aluminum hollow cross section
More definitions
Yield stress = the maximum stress that 6061T6 before it permanently stretches, ie will not rebound elastically to its original shape. 40,000 psi
Allowable stress= probably open to push back here but often a factor is introduced to deal with other metal failure issues. This is often taken as .8 of yield. So this number is 32,000 psi
So back to Sigma =Mc/I
Sigma max is 32,000, M is the same moment that the original mast was designed and that is 18,000 inch pounds. You want to see if a 3 inch x 1/8 wall mast will carry the same
as the 3 inch solid wood
32,000 = 18,000 x 1.5 / I I = 18,000 x 1.5 / 32000 = .844 inches to the 4th This is the moment of inertia that you would need for a hollow aluminum mast.
A 3 inch 6061T6 tube with 1/8 inch wall has an I of 1.2 prox. So the mast will carry the load.
Other factors to consider
1) you need to ensure that the mounting will not cause a stress concentration then failure
2) The modulus of elasticity of aluminum is about 9 times that of white spruce so it is stiffer
THE BIGGEST ASSUMPTION IS THAT THE 3 INCH SOLID WOOD MAST MEETS ALL OF THE LOADING THAT THE MAST MAY BE EXPOSED TO AND THAT A SUITABLE FACTOR OF SAFETY HAS BEEN INCLUDED.