Peter Binns
New Member
- Joined
- Mar 25, 2021
- Posts
- 3
- Reaction score
- 1
- Location
- Constantine, Cornwall, United Kingdom
Firstly, hands up, I am a marine modeler, not a real boat owner. However, whilst combing the web for information on how to calculate displacement I came across a very old post from Guillermo who said,
"You need to know waterline length, waterline beam, and body draught amidships (just body, not total draught under the keel). Then you need the "Block coefficient" which may vary a lot depending on hull forms. But for a rough estimative on a sail boat it should be not far away from 0.4
So if you multiply Lwl*Bwl*Hd*0.4 you get (roughly) the underwater volume of the hull. Now multiplying this by the weight density of water (If salt then it's around 1.025 tonnes/m3 or 64 lbs/ft3 depending on units chosen) you get the displacement weight in tonnes (if you chose measurements in metres) or pounds (if you did it in feet).
As said, this is a rough figure just to get a first idea. Being accurate takes quite a bit of more time and knowledge."
Because I am planning a new project - a 1:18 scale live steam-powered working model of a 1906 passenger steamer that worked on the River Fal in Cornwall, UK, for which I only have a poor copy of the original 'general arrangements' deck and profile drawings - I need to estimate the likely displacement of my model in order to select the size and specification of steam plant to power the vessel adequately. I have used the formula set out by Guillermo, but I am unsure as to what value of 'block co-efficient' I should use. As a yardstick he quotes 0.4 as typical for a sail boat, but the hull shape of my model is broad and fairly flat-bottomed, although as typical for the era, it has a vertical and fairly sharp bow line. I therefore adjusted the 'block co-efficient' to 0.7, thinking that the hull shape was a lot nearer to a floating cube than a sail boat!
I'd be grateful for any comments from big-boy boaters on this, or a better way to calculate displacement weight. I'm attaching the drawings I have (difficult to see at small size) and contemporary photo of the vessel in question.

Hope someone can help.
Many thanks.
"You need to know waterline length, waterline beam, and body draught amidships (just body, not total draught under the keel). Then you need the "Block coefficient" which may vary a lot depending on hull forms. But for a rough estimative on a sail boat it should be not far away from 0.4
So if you multiply Lwl*Bwl*Hd*0.4 you get (roughly) the underwater volume of the hull. Now multiplying this by the weight density of water (If salt then it's around 1.025 tonnes/m3 or 64 lbs/ft3 depending on units chosen) you get the displacement weight in tonnes (if you chose measurements in metres) or pounds (if you did it in feet).
As said, this is a rough figure just to get a first idea. Being accurate takes quite a bit of more time and knowledge."
Because I am planning a new project - a 1:18 scale live steam-powered working model of a 1906 passenger steamer that worked on the River Fal in Cornwall, UK, for which I only have a poor copy of the original 'general arrangements' deck and profile drawings - I need to estimate the likely displacement of my model in order to select the size and specification of steam plant to power the vessel adequately. I have used the formula set out by Guillermo, but I am unsure as to what value of 'block co-efficient' I should use. As a yardstick he quotes 0.4 as typical for a sail boat, but the hull shape of my model is broad and fairly flat-bottomed, although as typical for the era, it has a vertical and fairly sharp bow line. I therefore adjusted the 'block co-efficient' to 0.7, thinking that the hull shape was a lot nearer to a floating cube than a sail boat!
I'd be grateful for any comments from big-boy boaters on this, or a better way to calculate displacement weight. I'm attaching the drawings I have (difficult to see at small size) and contemporary photo of the vessel in question.

Hope someone can help.
Many thanks.