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Discussion in 'Stability' started by azri, Feb 22, 2012.

  1. daiquiri
    Joined: May 2004
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    Location: Italy (Garda Lake) and Croatia (Istria)

    daiquiri Engineering and Design

  2. azri
    Joined: Feb 2012
    Posts: 25
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    Location: malaysia

    azri Junior Member

    hi daiquiri, nice to meet you...tq for another thread...:)

    i already applied attwood formula in my calculation then it go like this, pls comment...;)

    using MS excel GZ=(GM+0.5*BM*TAN(THETA)^2)*SIN(THETA)

    stability at WL2, GM = 0.171 m , BM = 0.364

    for 0 to 90 degree of heel in step of 10, so the result is like this,

    0.0
    0.0
    0.1
    0.1
    0.2
    0.3
    0.6
    1.5
    5.9
    4.85014E+31

    using saintifik calculator (casio 570), the answer like this

    0
    -0.15
    0.11
    0.34
    0.067
    0.08
    0.15
    0.3
    -0.85
    0.171


    so, what your opinion???:eek:
     
  3. azri
    Joined: Feb 2012
    Posts: 25
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    Location: malaysia

    azri Junior Member


  4. Ad Hoc
    Joined: Oct 2008
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    Location: Japan

    Ad Hoc Naval Architect

    As noted in your other thread:-
    http://www.boatdesign.net/forums/stability/statical-stability-41917.html#post532033

    You will not get what you want from simple Q&A because your goal is above your present ability. You need to sit down with someone and discuss this. Preferably your tutor/boss.
     
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