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#1
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| Swain BS_36 Stability curve Just some stuff I've been looking at lately.Grist for mills... Swain BS_36 Stability curve...I assume data derived from"additional"? Some additional information: Estimated displacement D : 8.256 tonnes Z coordinate of CoG : 0.880 m Initial transverse metacentric height ho : 1.600 m Maximal GZ : 1.094 m Heeling angle for GZ maximum : 80.0 degr Heeling angle at which righting lever=0 again : 180.0 degr Maximum dynamic heeling angle : 120.0 degr ![]() KN sin(Psi) 0.0° 0.000 2.0° 0.087 5.0° 0.217 10.0° 0.428 15.0° 0.627 20.0° 0.816 25.0° 0.995 30.0° 1.162 35.0° 1.313 40.0° 1.445 45.0° 1.557 50.0° 1.651 55.0° 1.728 60.0° 1.789 65.0° 1.838 70.0° 1.882 75.0° 1.930 80.0° 1.960 85.0° 1.951 90.0° 1.924 95.0° 1.882 100.0° 1.825 105.0° 1.757 110.0° 1.677 115.0° 1.585 120.0° 1.482[ 125.0° 1.369 130.0° 1.249 135.0° 1.123 140.0° 0.995 145.0° 0.864 150.0° 0.731 155.0° 0.595 160.0° 0.455 170.0° 0.185 175.0° 0.079 180.0° 0.000 |
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#2
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| And where this BS is from? Don't say Brent has calculated it.. ROFL |
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#3
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| Quote:
(say, "Brent has calculated it") ...and the tenor of your comment informs me not to say who.But I do think whoever did it has the plans and the knowledge to model in 3d and took pains to be accurate.These are stability calculations for BS_36.Here they are.Enjoy. |
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#4
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| Enjoy for sure.. Looks like it's a new revised model of BS_36, anyway that form stability curve is typical for "plank on edge" boat.. Wonder thou where to put those famous "structurally superior" pilge keels in a boat without pilge.. ![]() |
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#5
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| Quote:
The data presented is highly questionable, it looks very much like the cog figures have been simply chosen to match a desired stability curve. I'd like to see the CG calculation, I think you'll find that's simply wrong, look at the supposed GM of 1.6 m ! An accurate and thorough weights and moments calc can come close to providing the CG providing the person conducting it has the experience to know what to include. Tad Roberts was offering to do an inclining test for Brent, that would be illustrative and it allows kG to be accurately derived.
__________________ Mike Johns. |
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#6
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__________________ Mike Johns. |
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#7
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| Looks good to me. These boats are anything but plank on edge. Their modest beam and combination trunk cabin and pilothouse give a huge amount of ultimate stability. |
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#8
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| For the viewers: Jack Hickson is Brent Swain. Brent if you really want to know you should take Tad up on his offer of an inclining test. You'll find that stability curve is junk. Anyone with a BS36 near Hobart can have the test done by me too for free. There's something very wrong with those figures. Send me your weights and moments calcs and I'll run it in a proper stability package free to trim and I'll check your CG.
__________________ Mike Johns. |
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#9
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| Sibqc...
__________________ Will Imaginocean Yacht Design Logic will get you from A to B... Imaginocean will take you everywhere else... www.imaginocean.net Last edited by Willallison : 03-09-2011 at 05:44 PM. Reason: New acronym...Standing In Background Quietly Chuckling |
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#10
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| Quote:
Anyway the weight (displacement) is wrong. The only actual weights I've ever seen posted as per crane hook load cell were over 20,000 lbs for a 36' BS boat and I assume that was with empty tanks. Junk2lee, you must have *known* that nobody here was going to accept a calculation like that without all the math and assumptions used to derive it. Are you just trolling or what? PDW |
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#11
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| Sadly you are deluded. Given that for GZ = KN – KG.sin(theta) So, KG you say is: And KN is given by: Quote:
2 degrees = 0.056m 5.0 = 0.010m 10. = -0.065m 15 = -0.141m 20 = -0.214m And so on…. DOH ![]() ....only first value is correct...should read below (still not woken up): |
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#12
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| Quote:
I can't argue them.That's for the pundits.I'm just the newshound here. Oh well.Go ahead,attack the newspaper.Blame the messenger.sigh. ![]() |
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#13
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| Quote:
Quote:
See above, a step by step guide how to perform the calculation. Quote:
The only "enjoyment", is seeing another person defending BS blindly after falling for the snake oil spin, AGAIN!!. After that amusement has faded, one is left feeling sad for the lack of professionalism and those wishing to follow a preacher burying their heads in the same sand as the preacher, rather than seek/listen to proper independent advice. |
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#14
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| Quote:
What did you expect would happen?? Post the source of the figures and you're off the hook, people can then look at who did it, how they did it and then see if their calcs come to the same conclusion. None of this is rocket science, it's basic scientific method, ditto engineering practice. It's not even BEST practice, just the minimum. I for one get really tired of trying to educate people, I no longer get paid to do it and I'm not real interested in trying to explain the same things to the same person/people the 3rd or 4th time. That's why I figure you're a troll, a sock-puppet or just lack the ability to learn. If this forum had a kill file a la usenet, the next post like this from you would get you residence. PDW |
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#15
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| Quote:
In my relaxed post holiday state state, I failed to re-input each KN for each angle, I forgot to use the new one….doh!!! ![]() ![]() ![]() However what is more amusing is that you didn’t realise this!... ![]() ![]() If you use the values you posted you get exactly that graph. BUT…at small angles of theata, the slope of the curve is equal to the GM at 1 radian. This is the back check to ensure the values are correct. So, looking at your graph…. GZ = GM (theta)….where for small angles theta is in radians. Thus take 2 degree, this values (is correct) 0.056 or we can say that GM = GZ/theta Hence GM = 0.056/(2/57.3) = 1.6044 This agrees with that given of 1.60 So, if we apply real stability conditions, what happens??...in other words, are those values real or just made up, for a given design?? Well, if a weight moves across the deck from side to side, how does this effect the GZ value? The new GZ = GZ(original) – (wh/W).cos(theta) If the boat is already heeled at 2 degrees, lets use these figures when taking an example of 1 person walking across the deck, from side to side (since we now have them). Width of deck approx 3.0m, weight of person 75kg. The new GZ at 2 degrees is 0.029m a drop from 0.056m! If we do the same but now with 2 people walking from side to side The new GZ at 2 degrees, with 2 ppl, is 0.002m If we do the same but now with 3 people walking from side to side The new GZ at 2 degrees, with 3 ppl, is -0.02m So if 3 people walk across the boat from side to side, the result is a negative GZ. The stability is reducing, and badly.. If we look at this for the 5 degrees The new GZ at 5 degrees, with 3 ppl, has gone from 0.14m to 0.06m This simple check does not take into account any rise in KG from these people stepping on board and walking across the deck. (The KG rises to 0.95m an increase of 0.07m with 3 persons on the deck, standing up). Which also affects those figures above. Thus, the figures posted on first appearance seem plausible, but upon closer scrutiny (apart from the rubbish 180 degree range of stability)do not hold up. Since once a simple stability check is introduced, shows the stability to be extremely poor. Dangerously so... |
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