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#1
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| Help with Keel Calculation Is there a calculation to determine the weight/length of a sailboats keel relative the boats weight/displacement/mast height? Thanks |
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#2
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| I think you should calculate the rightning moment for different angles of heel, and also the heeling moment with different sail configurations and wind speed. |
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#3
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| try looking at another boat that's the same size/displacement. look at the sail area, and then judge your keel accordingly based on what you want to do with it.
__________________ "...Macgregor owners are bitter as it is. It's like the gay guy who can't admit that he's gay." |
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#4
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| in the minitransat class (6.5 lwl/loa), there's a rather simple rule about stability: with the boat heeled at 90°, stability must be enough to be able to handle a weight of XX kgs from the top of the mast. (I don't know the XX by heart, I thought is was 30 kgs, but I'm not sure about this value) The boat must be able to either right itself from this load or to keep 90° equilibrium. bye Hans |
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#5
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| Quote:
![]() The 6.5m mini-Transat box rule is a neat challange.
__________________ Proud supporter of The Far Kurnell Cat Racing Team I have not failed. I've just found 10,000 ways that won't work. - Thomas A. Edison |
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#6
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| This (mini 6.5) is a simple (and good) rule for small boats where the keel bulb is not contributing much to stability when sailing, but is more of a safety factor. For narrower hulls or boats without much crew (or water ballast) weight you may want more ballast in the keel, like 30 to 50% of the total displacement. Remember, some years ago 50% was normal when total displacement meant the boat+crew+stores+everything, while now 25% of the empty boat seem to be quite normal. It depends of course on hull form. |
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#7
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| Quote:
45 kgs from the masthead of a mast at a bit over 90° heel, that normally towers 12 meters over LWL and all this on a boat just 6.5 m (appr. 23') long is an amazing amount of stability! I once soloed a Pogo (which is not a proto) on the Baltic. Great little yachts these are... cheers, Hans |
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#8
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| Thanks for all of the help. From what I understand you can get by with less weight in the keel IF you increase the length of the keel. Is there a formula for this? |
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#9
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| value of wieight multiplied by lenght must stay the same. Personaly I think that you shoul calculate moment of sails(I know it is not the corect name for this moment), and righting moment. tricky thing is to calsulate the forse created by wind going threw the sail (lift), there are several coeficients, which depends from sail shape and air densiti. Wind speed and AofA is very important, so you must decide in what conditions must sail. Formula looks like that: P*h=G*l P-lift h-distance from center of bouyancy to center of sail are G-gravity force l-gorizontal distance betveen center of boyiancy to the center of gravity P=(wind speed^2/16)*sail area*coeficient of sail efectivnes Sorry for english I have translated these formulas from my russian book
__________________ Lithuania |
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#10
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| Quote:
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