Data for a VPP?

Discussion in 'Sailboats' started by Joakim, Apr 1, 2004.

  1. nico
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    nico Senior Member

    In winvpp, i think the residual drag is interpolated with a cubic polynomial curve. I agree that a linear interpolation is not correct. Particularly for Fn around 0.4 where the values change a lot.
    LCBfpp is the distance in meters from the forward end of LWL
    LCB is as presented in table 2, and should be negative a LCB of -3.28 means a LCBfpp of LWL/2+3.28/100*LWL.
    What programming language are u using?
     
  2. tspeer
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    tspeer Senior Member

    Oops. I may have the sign wrong. As a practical matter I don't think you'll find any hulls that actually have the LCB ahead of midships.

    I'd say the taper ratio of the keel is 0.76, or a little less when you extrapolate the blade to the bottom of the bulb. The bulb is ignored for the purpose of defining the reference area.
     
  3. Joakim
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    Joakim Senior Member

    I'm using C language.

    I had already assumed that LCB would be the % values in table 2, but using a % value in residual drag equation does not seem to fit the logic used in other equations, which only uses non-dimensional parameter derived from actual measures (e.g. LCBfpp/LWL, VOLc^1/3 / LWL) and all the ratios (Cm, Cp) are in fractional from not in % (e.g. Cp=0.54 not 54%).

    I have also checked the excel sheet that Nico has sent here and in it LCB is given in %, but with a wrong sign, but it is only used to calculate LCBfpp. Even more confusing....

    Joakim
     
  4. nico
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    nico Senior Member

    in my spreadsheet LCB is positive but i have changed the sign in the equation that computes the residual drag -*- = +
     
  5. nico
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    nico Senior Member

    I think that the negative LCB in % is the way delft have described LCB from the start (for the last 25 years). With the LCBfpp/LWL they are probably moving to a form that is used most often used (ie. LCB=0.56).
    % is just an easier way to write fractionnal number
     
  6. MikeJohns
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    MikeJohns Senior Member


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