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#1
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| resistance scaling Hi, If I know the resistance curve (R vs speed) for one particular draft, is there a way to estimate the resistance for other draft? It does not need to be spot on estimation (maybe the likes of admiralty formula estimation). Best regards, -Arman- |
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#2
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| Do you mean if you increase the displacement of the vessel? The answer for that is no. The shape of the hull changes as it submerges deeper. You need to recalculate.
__________________ Gonzo |
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#3
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| Quote:
1. the hull does not have too much flare near the free surface, and 2. you know the beam and the shape of the waterplane and 3. you know the wetted area, then you can get a reasonable estimate for small changes in draft. You can estimate the viscous drag using a friction line in the standard way using the length and the wetted surface area. You can estimate the increase or decrease in surface area from the longitudinal girth multiplied by the change in draft, and hence you can estimate the change in skin-friction. Wave resistance can be assumed to vary with beam squared. So, multiply the original wave (or residuary) resistance by (B1/B0)^2, where B1 is the new beam. It's rough, but should give reasonable results quickly for small changes in draft. Good luck! Leo. |
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#4
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| Quote:
1) Wave resistance does not change with small displacement changes - or ? - 2) Wave resistance scales with displacement The suggestion above implies the answer is 1).
__________________ David Cockey |
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#5
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| The skin friction will not increase in direct proportion to displacement increase. Other parameters won't scale in direct proportion either. For example, prismatic coefficient.
__________________ Gonzo |
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#6
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| What about wave resistance, aka residuary resistance. Obviously it doesn't scale exactly with displacement, but is scaling with displacement a reasonable first order approximation?
__________________ David Cockey |
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#7
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| Quote:
It is simply pro-rata one displacement to the other as a ratio. Resistance at new displacement = (displ new/displ old) x resist at old displ. |
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#8
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| There are a few traps in all of these methods. IMO, it would be imprudent to apply them to hulls with large bulbous bows and/or large transom sterns, and possibly planing hulls. Last edited by Leo Lazauskas : 01-19-2012 at 03:55 PM. Reason: sp. |
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#9
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| Indeed. For example, a 10m boat, going from say 10 tonne to 20 tonne, is somewhat different from a 100m boat going from 500 tonne to 550 tonne. But, in understanding the generality, it works well, when used with common sense. |
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#10
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| You need not just common sense but experience to be able to interpret the results.
__________________ Gonzo |
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#11
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| Quote:
It is probably "between" 1) and 2) because wave effects tend to decrease exponentially with depth. |
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#12
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| That would be my guess also. What would be a good characteristic length for the decay, length corresponding to Froude number of 0.4?
__________________ David Cockey |
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#13
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| Perhaps the biggest problem in attempting to do this is regarding changes in trim. If the weight goes in anywhere other than the center of flotation, you mess up everything. If you started out at anywhere other than ideal trim you are also pretty much screwed. You can add weight to an out-of-trim canoe and significantly reduce resistance. In a sailboat, adding weight would effect leeway, heel, transom immersion, rudder angle and the dynamic response of the boat to the seas. Roll and pitch damping affect resistance in the real world, so changes in linear and rotational inertia are important considerations. There are rather drastic constrains to even trying to do this. However, if you can explain in gory detail where you're starting from and where you're ending up, maybe the forum can agree to ignore many of the above objections. |
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#14
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| Quote:
For example, set up a long thin parabolic strut (say L=10m, B=1m) with a draft of 1m. Use the sinkage option to float the "hull" at 0.5m and calculate the resistance. Then float it at 0.6m and calculate. Then 0.7m, etc. Plot wave resistance/Displacement weight as a function of Froude number. You can then try with a more realistic hull. I suggest a parabolic strut because: 1. input and results are easy to understand, 2. Michlet calculates the spectral functions exactly for parabolic struts and Wigley hulls, 3. Many post-processing calculations can be done by hand or in a spreadsheet. |
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#15
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| The resistance on a strut or keel is in part from the tip vortex. The would be the same regardless of displacement-draft.
__________________ Gonzo |
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