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| Question about ABS HSC 2012 Hello, In the rule 2012, I note that the design area factor (Fd) is not linked with the ratio Ad/Ar, but on the stiffener space for the craft < 24 m. Suppose that on a boat, the longitudinal space is 0.25 m, the transversal frame space is 1 m and transverse frame unsupported lenght is 3 m, is it correct to said that : Fd for plating is 0.85 Fd for longitudinal is 0.5 Fd for transversal frame is 0.4 It seems to me that this new rule is a simplificaton of the rule used for ABS ORY. Thank you in advance Best Regards Jacques |
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