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#1
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| Help SAVITSKY power prediction Hello I have to do a power prediction for a patrol of 20m in length using Savitskyīs method. The length is the only data i have, and I donīt know what parameters I have to suppose and how to get the power by this method. Can u help me, please? Thanks |
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#2
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| I don't think that you could reliably do a power prediction with so little information - whether by Savitsky or any other reasonable method. There are a number of variables that you could assume - like CG position for instance, but others, like displacement can vary so much that your predicition could by out by multiples of the correct number Take a look at this thread. Amongst other things, there is a link to a spreadsheet (by Dingo) with savitsk's Savitsky Power Prediction
__________________ Will Imaginocean Yacht Design |
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#3
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| Thank u Thank u very much Willallison I saw Dingoīs sheet, but I donīt have enough information to use it, and I think I canīt use any software. I have to explain the method and suppose as many things as necessary to get the power. Thank you again |
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#4
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| Give me displacement, hull shape (round or chine), propulsion system and power or speed..... |
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#5
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| Ah - ok - this is a 'school' question - thats different. You must go look at as many similar boats as possible and note down as much info about them as possible - displacement, deadrise, CG etc etc. Many things you wont be able to get info on - like CG for instance, so you will have to make an educated guess about its position
__________________ Will Imaginocean Yacht Design |
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#6
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| Data base Yes, itīs a school work. I donīt know anything about high speed vessels, and the only data I have is the length. I have to talk about forms, resistance, porposing, speed coefficient, give a table of planing vessels against Froude number and do a prediction of power by savitsky (I have to give a number). I made the following data base and I have found some information about the other things (not many), but I donīt know how to do the savitsky prediction of power. Thank you very much |
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#7
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| Hello I have read that the best option for this kind of patrol is: chine forms waterjets propulsion and I can suppose: displacement about 20 T max speed about 55-60 knots service speed 15-25 knots How can I do the power prediction? Can u tell me something about the speed coefficient? Thank you |
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#8
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| 20 t seams to be to optimistic for such top speed and waterjet propulsion plant... Anyway according to my KR system you will need 3100 hp abt. in order to reach 57.5 knots, but as sed in my opinion the displacement would be btw. 25/30t. KR = (BHP)^0.551 / (Displ.)^0.476 |
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#9
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| Thank you very much Otto, I will consider your prediction but I have to do it by Savitskyīs method. Thank you anyway. I will keep in mind your power prediction and weight |
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#10
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| Savitsky ,according to my own experience based on model test results, is too optimistic... The input for a such patrol boat would be: Length at waterline = 17.00 m > 55.77 ' Beam = 5.2 m > 17.1' Deadrise angle = 18.5 deg. L.c.g. = 6.3 m > 20.7 ' Displacement = 27.5 t > 60'627 lbs try to calculate the bare hull resistance with Sav. with these data... |
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#11
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| I would like to try with Savitsky, but I have a little problem. I donīt know what Savisky said! |
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#12
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| I think what Chocomono is looking for is a copy of savitsky's method. I'd post one but I don't have it handy - or in electronic format either...
__________________ Will Imaginocean Yacht Design |
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#13
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| Youīre right. I want to know how is the method or what Savitsky said. What I have to suppose and how can I get the power prediction. Thanks |
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#14
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| http://www.sname.org/newsletter/Savitskyreport.pdf#search='Daniel%20Savitsky' Try this link or what was suppose to be a link, anyway good luck.
__________________ Calm days, Tides Running, and Fish Biting What more could you ask for? Bruce |
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#15
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| Thank you very much! Savitskyīs method is not explained in this article but itīs interesting and I think it will be very helpful for my homework. Thank you again Anyone can attach the method? |
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