View Full Version : Drag Forces on a Flat Face Barge

mitch10284

03-05-2013, 12:17 PM

Hello. I'm working on constructing an anchoring system for Barges on the MississippI River in St Louis and need to determine the force the river will impose on an anchored barge. I'm using the Drag Force Equation

F = 1/2 x velocity^2 x density x Area x Cd

Assumptions

Drag Coefficients

Cd = 1.98 for the bow

Cd = .005 for bottom and sides

Density = 62.4 lb/ft^3 for water

Barge is 35'x195' and sits 11' in the water

I've been told by a few Barge Captains the river can reach 26 ft/s during a strong flood. I'm designing for worst case so I've used this number.

The problem I'm having is that the drag force numbers I'm getting seem to be way high.

Bow - 16,576,329 lb

Sides - 466,433 lb

Bottom - 742,053 lb

Hoping someone can confirm these numbers are incorrect and can help me out.

Thank You

F = 1/2 x velocity^2 x density x Area x Cd

Assumptions

Drag Coefficients

Cd = 1.98 for the bow

Cd = .005 for bottom and sides

Density = 62.4 lb/ft^3 for water

Barge is 35'x195' and sits 11' in the water

I've been told by a few Barge Captains the river can reach 26 ft/s during a strong flood. I'm designing for worst case so I've used this number.

The problem I'm having is that the drag force numbers I'm getting seem to be way high.

Bow - 16,576,329 lb

Sides - 466,433 lb

Bottom - 742,053 lb

Hoping someone can confirm these numbers are incorrect and can help me out.

Thank You

Submarine Tom

03-05-2013, 12:30 PM

Isn't water density 1.0?

Don't discount windage.

Don't discount windage.

mitch10284

03-05-2013, 12:36 PM

Using US Customary Units and the Mississippi is fresh water in St Louis.

Regards

Regards

TANSL

03-05-2013, 01:00 PM

Can be Cd bigger than 1?

DCockey

03-05-2013, 01:39 PM

Can be Cd bigger than 1?

Yes. Nothing special about a Cd value of 1. The table in my old fluid mechanics textbook shows a drag coefficient of 2.00 for an infinitely wide flat plate normal to the flow, 1.20 for a rectangular flat plate with an aspect ratio of 5 normal to the flow, and 1.10 for a square plate normal to the flow. Those are drag coefficients for an object completely immersed in an "infinite" flow.

Yes. Nothing special about a Cd value of 1. The table in my old fluid mechanics textbook shows a drag coefficient of 2.00 for an infinitely wide flat plate normal to the flow, 1.20 for a rectangular flat plate with an aspect ratio of 5 normal to the flow, and 1.10 for a square plate normal to the flow. Those are drag coefficients for an object completely immersed in an "infinite" flow.

DCockey

03-05-2013, 01:44 PM

Hello. I'm working on constructing an anchoring system for Barges on the MississippI River in St Louis and need to determine the force the river will impose on an anchored barge. I'm using the Drag Force Equation

F = 1/2 x velocity^2 x density x Area x Cd

Assumptions

Drag Coefficients

Cd = 1.98 for the bow

Cd = .005 for bottom and sides

Density = 62.4 lb/ft^3 for water

Barge is 35'x195' and sits 11' in the water

I've been told by a few Barge Captains the river can reach 26 ft/s during a strong flood. I'm designing for worst case so I've used this number.

The problem I'm having is that the drag force numbers I'm getting seem to be way high.

Bow - 16,576,329 lb

Sides - 466,433 lb

Bottom - 742,053 lb

Hoping someone can confirm these numbers are incorrect and can help me out.

Thank You

You need to divide by the "density" of water of 64.4 lb/ft^3 by 32.2 ft/sec^2 to obtain the mass density of 2.0 slugs/ft^3. That will reduce the drag force numbers by a factor of 32.2.

F = 1/2 x velocity^2 x density x Area x Cd

Assumptions

Drag Coefficients

Cd = 1.98 for the bow

Cd = .005 for bottom and sides

Density = 62.4 lb/ft^3 for water

Barge is 35'x195' and sits 11' in the water

I've been told by a few Barge Captains the river can reach 26 ft/s during a strong flood. I'm designing for worst case so I've used this number.

The problem I'm having is that the drag force numbers I'm getting seem to be way high.

Bow - 16,576,329 lb

Sides - 466,433 lb

Bottom - 742,053 lb

Hoping someone can confirm these numbers are incorrect and can help me out.

Thank You

You need to divide by the "density" of water of 64.4 lb/ft^3 by 32.2 ft/sec^2 to obtain the mass density of 2.0 slugs/ft^3. That will reduce the drag force numbers by a factor of 32.2.

View Full Version : Drag Forces on a Flat Face Barge

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