Akgramps
10-11-2008, 01:08 PM
Can anyone explain how to detrmine the Longitudinal center of gravity (LCG) on a particular boat?
Thanks
Guest625101138
10-11-2008, 06:00 PM
Make a 4 column table listing all of the components and pieces that go together to make the boat listing their individual weight and distance from the stern.
In a fourth column multiply the weight by the distance to get moments. Add up all the weights to get total weight and add up all the moments to get total moment. Now divide the total moment by the total weight. The answer is the distance of the LCG from the stern.
If the boat is already built and in the water you can do a simpler exercise by determining the change in pitch with a change in weight distribution and calculating from that information.
Rick W
Akgramps
10-11-2008, 10:55 PM
Rick,
Thanks for the reply and info, Yeah this boat is done. It is a 20 foot aluminum riverboat with a warped hull and is very sensitive to bow steering. I have modified the top of the tunnel, it was angling down and acting like abig trim tab, pushing the bow down. Angling it up slightly has made an immense improvement.
I think it can be better, I have read warped hulls are more senistive to LCG as they tend to have flatter trim and more wetted surface. Hence the question about LCG. I am thinking thats not so impotant now as I can always adjust the load if the boat is loaded heavy.
I want to add some lifting dtarkes and have a design in mind, dont know if its right? and dont know if I should run them all the way to the transom?